If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9n^2+41n=0
a = 9; b = 41; c = 0;
Δ = b2-4ac
Δ = 412-4·9·0
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-41}{2*9}=\frac{-82}{18} =-4+5/9 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+41}{2*9}=\frac{0}{18} =0 $
| .023b+5=20-b | | 3(m+-4)=2m+3 | | 7(4+5)=6(x-2)+15 | | 24=2(c-66) | | -50x+20=120 | | -3(2j/3-6)=36 | | 24=2(c−66) | | X/3=x/3+4 | | 4(6x-2)=2(3x/4+5 | | 56x^2-87x=0 | | 7s^2+39s=0 | | -2x-9=21 | | 4^x=3/2x+7 | | 4.6b+26.8=50.7 | | -3x-14=2x+16 | | 16+7m-5+m=11m-3-m | | 3(x-3)+3/10=9 | | 31t=186 | | -6-9r=39 | | 6(3a+8)=-60 | | 7(4x+10)/5=-1 | | -3p-6=-6 | | b-14=0 | | .04(x)+x=40000 | | 1.6x+0.3x=21.6+2.3x | | 9+35b=710b | | x*(2x-6)=0 | | 2/3*g+6=-12 | | 4t−-12=96 | | 12=2-x/5 | | 3x-6/5=12 | | 4p-17=55 |